What is factor 2(x^2+4x)-5 ?

The solution to factor 2(x^2+4x)-5 is 2(x-(sqrt(26)-4)/2)(x-(-4-sqrt(26))/2)

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factor 2(x^2+4x)-5

factor

2 (x^{2} + 4 x) - 5

2 (x - \frac{26 - 4}{2}) (x - \frac{- 4 - 26}{2})

Solution steps

2 (x^{2} + 4 x) - 5

2 (x^{2} + 4 x) = 2 x (x + 4)

= 2 x (x + 4) - 5

Expand

2 x (x + 4) - 5 : 2 x^{2} + 8 x - 5

= 2 x^{2} + 8 x - 5

Factor

2 x^{2} + 8 x - 5 : 2 (x - \frac{- 4 + 26}{2}) (x - \frac{- 4 - 26}{2})

= 2 (x - \frac{26 - 4}{2}) (x - \frac{- 4 - 26}{2})

f (2 x^{2})

2 x + 1 - x - 1

a x^{2} - b x^{2} + a c - b c

175

x^{2} + 10 + 25

What is factor 2(x^2+4x)-5 ?
The solution to factor 2(x^2+4x)-5 is 2(x-(sqrt(26)-4)/2)(x-(-4-sqrt(26))/2)