What is factor 1+e^7 ?

The solution to factor 1+e^7 is (e+1)(e^6-e^5+e^4-e^3+e^2-e+1)

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factor 1+e^7

factor

1 + e^{7}

(e + 1) (e^{6} - e^{5} + e^{4} - e^{3} + e^{2} - e + 1)

Solution steps

1 + e^{7}

Rewrite

1

1^{7}

= e^{7} + 1^{7}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1})

n is odd

e^{7} + 1^{7} = (e + 1) (e^{6} - e^{5} + e^{4} - e^{3} + e^{2} - e + 1)

= (e + 1) (e^{6} - e^{5} + e^{4} - e^{3} + e^{2} - e + 1)

\frac{d}{d y} ((x (y)) (y^{3}))

x^{2 n - 4} - y^{4 n - 12}

(a + b) + (b^{'} c)

\frac{2}{x ^{2} + 10 x + 24}

f (x) = 2 x + 7

What is factor 1+e^7 ?
The solution to factor 1+e^7 is (e+1)(e^6-e^5+e^4-e^3+e^2-e+1)