What are the solutions to the equation -9x^2+18x=14 ?

The solutions to the equation -9x^2+18x=14 are x=1-i(sqrt(5))/3 ,x=1+i(sqrt(5))/3

Find the zeros of -9x^2+18x=14

The zeros of -9x^2+18x=14 are x=1-i(sqrt(5))/3 ,x=1+i(sqrt(5))/3

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- 9 x^{2} + 18 x = 14

x = 1 - i \frac{5}{3}, x = 1 + i \frac{5}{3}

Solution steps

- 9 x^{2} + 18 x = 14

Move

14

to the left side

- 9 x^{2} + 18 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 9 ) ( - 14 )}{2 ( - 9 )}

Simplify

1 8^{2} - 4 (- 9) (- 14) : 65 i

x_{1, 2} = \frac{- 18 \pm 6 5 i}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 18 + 6 5 i}{2 ( - 9 )}, x_{2} = \frac{- 18 - 6 5 i}{2 ( - 9 )}

x = \frac{- 18 + 6 5 i}{2 ( - 9 )} : 1 - i \frac{5}{3}

x = \frac{- 18 - 6 5 i}{2 ( - 9 )} : 1 + i \frac{5}{3}

The solutions to the quadratic equation are:

x = 1 - i \frac{5}{3}, x = 1 + i \frac{5}{3}

a^{2} b + a^{4} b^{2}

(\frac{4}{5})^{4}

4 x \geq - 8

t - 3 (4 - t) = - 24

3 x - 4 < 6 x - 7 < 3 x + 5

What are the solutions to the equation -9x^2+18x=14 ?
The solutions to the equation -9x^2+18x=14 are x=1-i(sqrt(5))/3 ,x=1+i(sqrt(5))/3
Find the zeros of -9x^2+18x=14
The zeros of -9x^2+18x=14 are x=1-i(sqrt(5))/3 ,x=1+i(sqrt(5))/3