What is factor 2y^{-1}+11y^{-4} ?

The solution to factor 2y^{-1}+11y^{-4} is (2y^3+11)/(y^4)

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factor 2y^{-1}+11y^{-4}

factor

2 y^{- 1} + 11 y^{- 4}

\frac{2 y ^{3} + 11}{y ^{4}}

Solution steps

2 y^{- 1} + 11 y^{- 4}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

y^{- 1} = y^{- 4} y^{3}

= 2 y^{- 4} y^{3} + 11 y^{- 4}

Factor out common term

y^{- 4}

= y^{- 4} (2 y^{3} + 11)

Refine

= \frac{2 y ^{3} + 11}{y ^{4}}

2 (a + b)^{2} + 3 (a + b) - 2

(a \cdot b) + (a \cdot c)

49 m 6 - 70 am 3 n 2 + 25 a 2 n 4

3 sin (2 x + 2)

(\frac{3}{5} x - 5)^{3}

What is factor 2y^{-1}+11y^{-4} ?
The solution to factor 2y^{-1}+11y^{-4} is (2y^3+11)/(y^4)