What are the solutions to the equation pir^2=28.26 ?

The solutions to the equation pir^2=28.26 are r=sqrt((28.26)/pi),r=-sqrt((28.26)/pi)

Find the zeros of pir^2=28.26

The zeros of pir^2=28.26 are r=sqrt((28.26)/pi),r=-sqrt((28.26)/pi)

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π r^{2} = 28.26

r = \frac{28.26}{π}, r = - \frac{28.26}{π}

Solution steps

π r^{2} = 28.26

Divide both sides by

π

r^{2} = \frac{28.26}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{28.26}{π}, r = - \frac{28.26}{π}

\frac{1}{2} \leq \frac{( 1 - 2 t )}{3} < \frac{2}{3}

572

x^{2} - 15 x y + 26 y^{2}

x + 14 = - 6

x^{3} + 5 x^{2} + 9 x + 45

What are the solutions to the equation pir^2=28.26 ?
The solutions to the equation pir^2=28.26 are r=sqrt((28.26)/pi),r=-sqrt((28.26)/pi)
Find the zeros of pir^2=28.26
The zeros of pir^2=28.26 are r=sqrt((28.26)/pi),r=-sqrt((28.26)/pi)