What is factor (p+q)^2+8(p+q)+16 ?

The solution to factor (p+q)^2+8(p+q)+16 is (p+q+4)^2

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factor (p+q)^2+8(p+q)+16

factor

(p + q)^{2} + 8 (p + q) + 16

(p + q + 4)^{2}

Solution steps

(p + q)^{2} + 8 (p + q) + 16

Rewrite

(p + q)^{2} + 8 (p + q) + 16

(p + q)^{2} + 2 (p + q) \cdot 4 + 4^{2}

= (p + q)^{2} + 2 (p + q) \cdot 4 + 4^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = (p + q), b = 4

= ((p + q) + 4)^{2}

Refine

= (p + q + 4)^{2}

\frac{x ^{6} - 1}{x ^{2} - 1}

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e^{ik x} - e^{- ik x}

What is factor (p+q)^2+8(p+q)+16 ?
The solution to factor (p+q)^2+8(p+q)+16 is (p+q+4)^2