What is factor 0.01a^2-b^2c^4 ?

The solution to factor 0.01a^2-b^2c^4 is (0.1a+bc^2)(0.1a-bc^2)

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factor 0.01a^2-b^2c^4

factor

0.01 a^{2} - b^{2} c^{4}

(0.1 a + b c^{2}) (0.1 a - b c^{2})

Solution steps

0.01 a^{2} - b^{2} c^{4}

Rewrite

b^{2} c^{4}

(b c^{2})^{2}

= 0.01 a^{2} - (b c^{2})^{2}

Rewrite

0.01 a^{2} - (b c^{2})^{2}

(0.01 a)^{2} - (b c^{2})^{2}

= (0.01 a)^{2} - (b c^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(0.01 a)^{2} - (b c^{2})^{2} = (0.01 a + b c^{2}) (0.01 a - b c^{2})

= (0.01 a + b c^{2}) (0.01 a - b c^{2})

0.01 = 0.1

= (0.1 a + b c^{2}) (0.1 a - b c^{2})

e^{ja t} u [t]

9 x^{6} - x

[3 x]

49 x 9 - 8 oy 2

\frac{1 - x}{2 x ^{2} - 5 x - 3}

What is factor 0.01a^2-b^2c^4 ?
The solution to factor 0.01a^2-b^2c^4 is (0.1a+bc^2)(0.1a-bc^2)