What is factor (2t-1)^2+7(2t-1)+10 ?

The solution to factor (2t-1)^2+7(2t-1)+10 is 2(t+2)(2t+1)

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factor (2t-1)^2+7(2t-1)+10

factor

(2 t - 1)^{2} + 7 (2 t - 1) + 10

2 (t + 2) (2 t + 1)

Solution steps

(2 t - 1)^{2} + 7 (2 t - 1) + 10

Expand

(2 t - 1)^{2} + 7 (2 t - 1) + 10 : 4 t^{2} + 10 t + 4

= 4 t^{2} + 10 t + 4

Factor

4 t^{2} + 10 t + 4 : 2 (2 t + 1) (t + 2)

= 2 (t + 2) (2 t + 1)

l (t e^{a t} sin (b t))

e^{(l n (y))^{l n (x)}}

sin^{2} (x) + 2 sin (x) + 1

- \frac{4}{5} x + 8

[cos (5 x - 9)]

What is factor (2t-1)^2+7(2t-1)+10 ?
The solution to factor (2t-1)^2+7(2t-1)+10 is 2(t+2)(2t+1)