What is factor y^5+m^5b^5 ?

The solution to factor y^5+m^5b^5 is (y+bm)(y^4-by^3m+b^2y^2m^2-b^3ym^3+b^4m^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor y^5+m^5b^5

factor

y^{5} + m^{5} b^{5}

(y + bm) (y^{4} - b y^{3} m + b^{2} y^{2} m^{2} - b^{3} y m^{3} + b^{4} m^{4})

Solution steps

y^{5} + m^{5} b^{5}

Rewrite

m^{5} b^{5}

(mb)^{5}

= y^{5} + (mb)^{5}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1})

n is odd

y^{5} + (mb)^{5} = (y + mb) (y^{4} - y^{3} mb + y^{2} (mb)^{2} - y (mb)^{3} + (mb)^{4})

= (y + mb) (y^{4} - y^{3} mb + y^{2} (mb)^{2} - y (mb)^{3} + (mb)^{4})

Simplify

(y + mb) (y^{4} - y^{3} mb + y^{2} (mb)^{2} - y (mb)^{3} + (mb)^{4}) : (y + bm) (y^{4} - b y^{3} m + b^{2} y^{2} m^{2} - b^{3} y m^{3} + b^{4} m^{4})

= (y + bm) (y^{4} - b y^{3} m + b^{2} y^{2} m^{2} - b^{3} y m^{3} + b^{4} m^{4})

(5 tan (5 x))^{2}

2 π^{2} + 2 π r h

2 π (sin (x))

10 x^{49} + 6.25 x^{168.7} - 5 x^{16}

f (x) = sin (x) + cos (x)

What is factor y^5+m^5b^5 ?
The solution to factor y^5+m^5b^5 is (y+bm)(y^4-by^3m+b^2y^2m^2-b^3ym^3+b^4m^4)