What is factor x^{10}+9x^5+8 ?

The solution to factor x^{10}+9x^5+8 is (x+1)(x^4-x^3+x^2-x+1)(x^5+8)

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factor x^{10}+9x^5+8

factor

x^{10} + 9 x^{5} + 8

(x + 1) (x^{4} - x^{3} + x^{2} - x + 1) (x^{5} + 8)

Solution steps

x^{10} + 9 x^{5} + 8

Use the rational root theorem

= (x + 1) \frac{x ^{10} + 9 x ^{5} + 8}{x + 1}

\frac{x ^{10} + 9 x ^{5} + 8}{x + 1} = x^{9} - x^{8} + x^{7} - x^{6} + x^{5} + 8 x^{4} - 8 x^{3} + 8 x^{2} - 8 x + 8

= (x + 1) (x^{9} - x^{8} + x^{7} - x^{6} + x^{5} + 8 x^{4} - 8 x^{3} + 8 x^{2} - 8 x + 8)

Factor

x^{9} - x^{8} + x^{7} - x^{6} + x^{5} + 8 x^{4} - 8 x^{3} + 8 x^{2} - 8 x + 8 : (x^{4} - x^{3} + x^{2} - x + 1) (x^{5} + 8)

= (x + 1) (x^{4} - x^{3} + x^{2} - x + 1) (x^{5} + 8)

x^{2} + 3 x - 28 x^{2} + 3 x - 28

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2 x a + 2 x b - a y - b y

e^{(3 x)} sin (5 x)

arccos (8 x - 4)

What is factor x^{10}+9x^5+8 ?
The solution to factor x^{10}+9x^5+8 is (x+1)(x^4-x^3+x^2-x+1)(x^5+8)