What is factor (x^6)/8-27y^3 ?

The solution to factor (x^6)/8-27y^3 is ((x^2)/2-3y)((3x^2y)/2+(x^4)/4+9y^2)

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factor (x^6)/8-27y^3

factor

\frac{x ^{6}}{8} - 27 y^{3}

(\frac{x ^{2}}{2} - 3 y) (\frac{3 x ^{2} y}{2} + \frac{x ^{4}}{4} + 9 y^{2})

Solution steps

\frac{x ^{6}}{8} - 27 y^{3}

Rewrite

\frac{x ^{6}}{8} - 27 y^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

Refine

= (\frac{x ^{2}}{2} - 3 y) (\frac{3 x ^{2} y}{2} + \frac{x ^{4}}{4} + 9 y^{2})

1 + (\frac{d y}{d x})^{2}

4 kn + 3 mn + 16 jk + 12 jm

3^{x + 2} - 3^{x}

3 a x + 2 a y - 3 b x - 2 b y

- 5 (x)^{2}

What is factor (x^6)/8-27y^3 ?
The solution to factor (x^6)/8-27y^3 is ((x^2)/2-3y)((3x^2y)/2+(x^4)/4+9y^2)