What are the solutions to the equation (x-1)(x-2)=6 ?

The solutions to the equation (x-1)(x-2)=6 are x=4,x=-1

Find the zeros of (x-1)(x-2)=6

The zeros of (x-1)(x-2)=6 are x=4,x=-1

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(x - 1) (x - 2) = 6

x = 4, x = - 1

Solution steps

(x - 1) (x - 2) = 6

Expand

(x - 1) (x - 2) : x^{2} - 3 x + 2

x^{2} - 3 x + 2 = 6

Move

6

to the left side

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

(n^{3})^{\frac{2}{5}}

40 + 7 t + \frac{1}{2} (- 9.81) t^{2} = 0 + 29 t + \frac{1}{2} (9.81) t^{2}

b - 4 + 8 b = 19

3 x - 5 x^{2}

6 x^{2} - 25 x - 9

What are the solutions to the equation (x-1)(x-2)=6 ?
The solutions to the equation (x-1)(x-2)=6 are x=4,x=-1
Find the zeros of (x-1)(x-2)=6
The zeros of (x-1)(x-2)=6 are x=4,x=-1