What is factor 2e^5+4*cos(5)dx ?

The solution to factor 2e^5+4*cos(5)dx is 2(e^5+2cos(5)dx)

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factor 2e^5+4*cos(5)dx

factor

2 e^{5} + 4 \cdot cos (5) d x

2 (e^{5} + 2 cos (5) d x)

Solution steps

2 e^{5} + 4 cos (5) d x

Rewrite as

= 2 e^{5} + 2 \cdot 2 cos (5) d x

Factor out common term

2

= 2 (e^{5} + 2 cos (5) d x)

6 + 106

s q u a re x^{2} + x

mn + 1 + 2 mn + 2 a

arccos^{4} (2 x - 2)

\frac{d}{d y} ((x) (sin (y)))

What is factor 2e^5+4*cos(5)dx ?
The solution to factor 2e^5+4*cos(5)dx is 2(e^5+2cos(5)dx)