What is factor (3x^2-3x-3)/(-3x) ?

The solution to factor (3x^2-3x-3)/(-3x) is -(x^2-x-1)/x

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factor (3x^2-3x-3)/(-3x)

factor

\frac{3 x ^{2} - 3 x - 3}{- 3 x}

- \frac{x ^{2} - x - 1}{x}

Solution steps

\frac{3 x ^{2} - 3 x - 3}{- 3 x}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 x ^{2} - 3 x - 3}{3 x}

Cancel

\frac{3 x ^{2} - 3 x - 3}{3 x} : \frac{x ^{2} - x - 1}{x}

= - \frac{x ^{2} - x - 1}{x}

a e^{x} + b e^{- x} + c e^{3 x}

1 - 1 - x^{2}

\frac{4 x}{12}

3 a - b^{(2)} + 2 b^{(2)} x - 6 a x

x + y + (- 1)

What is factor (3x^2-3x-3)/(-3x) ?
The solution to factor (3x^2-3x-3)/(-3x) is -(x^2-x-1)/x