What is factor (2x-y)^2-8(2x-y)+16 ?

The solution to factor (2x-y)^2-8(2x-y)+16 is (2x-y-4)^2

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factor (2x-y)^2-8(2x-y)+16

factor

(2 x - y)^{2} - 8 (2 x - y) + 16

(2 x - y - 4)^{2}

Solution steps

(2 x - y)^{2} - 8 (2 x - y) + 16

Rewrite

(2 x - y)^{2} - 8 (2 x - y) + 16

(2 x - y)^{2} - 2 (2 x - y) \cdot 4 + 4^{2}

= (2 x - y)^{2} - 2 (2 x - y) \cdot 4 + 4^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = (2 x - y), b = 4

= ((2 x - y) - 4)^{2}

Refine

= (2 x - y - 4)^{2}

(x - 0.4 x) - 0.4 (x - 0.4 x)

2 + 2 i 3

r (36 π)

2 + i 2

[cos (x^{2} + 3 x)]

What is factor (2x-y)^2-8(2x-y)+16 ?
The solution to factor (2x-y)^2-8(2x-y)+16 is (2x-y-4)^2