What are the solutions to the equation x=x^2-2 ?

The solutions to the equation x=x^2-2 are x=2,x=-1

Find the zeros of x=x^2-2

The zeros of x=x^2-2 are x=2,x=-1

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x = x^{2} - 2

x = 2, x = - 1

Solution steps

x = x^{2} - 2

Switch sides

x^{2} - 2 = x

Move

x

to the left side

x^{2} - 2 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

3 x + 1 < 7

\frac{15}{5} = \frac{y}{4}

\frac{2 x - 5}{3} = 9

25 6^{- \frac{5}{4}}

\frac{3 x}{5 ( x + y )} - \frac{2 y}{3 ( x + y )}

What are the solutions to the equation x=x^2-2 ?
The solutions to the equation x=x^2-2 are x=2,x=-1
Find the zeros of x=x^2-2
The zeros of x=x^2-2 are x=2,x=-1