What is factor 27f^3g^3-64h^3j^3 ?

The solution to factor 27f^3g^3-64h^3j^3 is (3fg-4jh)(9f^2g^2+12jfgh+16j^2h^2)

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factor 27f^3g^3-64h^3j^3

factor

27 f^{3} g^{3} - 64 h^{3} j^{3}

(3 f g - 4 jh) (9 f^{2} g^{2} + 12 j f g h + 16 j^{2} h^{2})

Solution steps

27 f^{3} g^{3} - 64 h^{3} j^{3}

Rewrite

27 f^{3} g^{3}

(3 f g)^{3}

Rewrite

64 h^{3} j^{3}

(2^{2} hj)^{3}

= (3 f g)^{3} - (2^{2} hj)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(3 f g)^{3} - (2^{2} hj)^{3} = (3 f g - 2^{2} hj) ((3 f g)^{2} + 3 f g 2^{2} hj + (2^{2} hj)^{2})

= (3 f g - 2^{2} hj) ((3 f g)^{2} + 3 f g 2^{2} hj + (2^{2} hj)^{2})

Simplify

(3 f g - 2^{2} hj) ((3 f g)^{2} + 3 f g \cdot 2^{2} hj + (2^{2} hj)^{2}) : (3 f g - 4 jh) (9 f^{2} g^{2} + 12 j f g h + 16 j^{2} h^{2})

= (3 f g - 4 jh) (9 f^{2} g^{2} + 12 j f g h + 16 j^{2} h^{2})

3 x + (- 5)

8 am + 4 an - 6 m - 3 n

3 12 + 23

(x + 2 i) (x - 2 i)

[3 x + y]

What is factor 27f^3g^3-64h^3j^3 ?
The solution to factor 27f^3g^3-64h^3j^3 is (3fg-4jh)(9f^2g^2+12jfgh+16j^2h^2)