What is factor [sec(χ)+tan(χ)][1-sin(χ)] ?

The solution to factor [sec(χ)+tan(χ)][1-sin(χ)] is -(sec(χ)+tan(χ))(sin(χ)-1)

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factor [sec(χ)+tan(χ)][1-sin(χ)]

factor

[sec (χ) + tan (χ)] [1 - sin (χ)]

- (sec (χ) + tan (χ)) (sin (χ) - 1)

Solution steps

(sec (χ) + tan (χ)) (1 - sin (χ))

Factor

1 - sin (χ) : - (sin (χ) - 1)

= - (sec (χ) + tan (χ)) (sin (χ) - 1)

f (s) = s^{2} + 4

x^{2} + 4 x - y^{2} - 2 y + 4 - 1

(I n) 5

3 x - 2 y + 2 y z^{4} - 3 x z^{4}

(x + 3) (x + 3)

What is factor [sec(χ)+tan(χ)][1-sin(χ)] ?
The solution to factor [sec(χ)+tan(χ)][1-sin(χ)] is -(sec(χ)+tan(χ))(sin(χ)-1)