What is factor 4x^2-16+15 ?

The solution to factor 4x^2-16+15 is (2x+1)(2x-1)

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factor 4x^2-16+15

factor

4 x^{2} - 16 + 15

(2 x + 1) (2 x - 1)

Solution steps

4 x^{2} - 16 + 15

Add/Subtract the numbers:

- 16 + 15 = - 1

= 4 x^{2} - 1

Rewrite

4 x^{2} - 1

(2 x)^{2} - 1^{2}

= (2 x)^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 x)^{2} - 1^{2} = (2 x + 1) (2 x - 1)

= (2 x + 1) (2 x - 1)

81 e^{2} - 180 e + 100

2 (^{'})

212103 (4)

cos (2 x - 10)

14 - 7