What is factor (x^3-1)/(x^4-1) ?

The solution to factor (x^3-1)/(x^4-1) is (x^2+x+1)/((x^2+1)(x+1))

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factor (x^3-1)/(x^4-1)

factor

\frac{x ^{3} - 1}{x ^{4} - 1}

\frac{x ^{2} + x + 1}{( x ^{2} + 1 ) ( x + 1 )}

Solution steps

\frac{x ^{3} - 1}{x ^{4} - 1}

Factor

x^{3} - 1 : (x - 1) (x^{2} + x + 1)

= \frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{4} - 1}

Factor

x^{4} - 1 : (x^{2} + 1) (x + 1) (x - 1)

= \frac{( x - 1 ) ( x ^{2} + x + 1 )}{( x ^{2} + 1 ) ( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x ^{2} + x + 1}{( x ^{2} + 1 ) ( x + 1 )}

+ 2 x y - 6 y + x z - 3 z

(5) - (3)

tan^{5} (x) + cot^{5} (x)

cosh (n x) + sin (h) (n x)

x^{2 + x - 2}

What is factor (x^3-1)/(x^4-1) ?
The solution to factor (x^3-1)/(x^4-1) is (x^2+x+1)/((x^2+1)(x+1))