What is factor x^6-12x^4+48x^2-64 ?

The solution to factor x^6-12x^4+48x^2-64 is (x+2)^3(x-2)^3

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factor x^6-12x^4+48x^2-64

factor

x^{6} - 12 x^{4} + 48 x^{2} - 64

(x + 2)^{3} (x - 2)^{3}

Solution steps

x^{6} - 12 x^{4} + 48 x^{2} - 64

Let

u = x^{2}

= u^{3} - 12 u^{2} + 48 u - 64

Factor

u^{3} - 12 u^{2} + 48 u - 64 : (u - 4) (u - 4) (u - 4)

= (u - 4) (u - 4) (u - 4)

Substitute back

u = x^{2}

= (x^{2} - 4) (x^{2} - 4) (x^{2} - 4)

Factor

x^{2} - 4 : (x + 2) (x - 2)

= (x + 2) (x - 2) (x^{2} - 4) (x^{2} - 4)

Factor

x^{2} - 4 : (x + 2) (x - 2)

= (x + 2) (x - 2) (x + 2) (x - 2) (x^{2} - 4)

Factor

x^{2} - 4 : (x + 2) (x - 2)

= (x + 2) (x - 2) (x + 2) (x - 2) (x + 2) (x - 2)

Refine

= (x + 2)^{3} (x - 2)^{3}

x^{2 + 14 x + 49}

x^{2} - 17 + 72

(x^{2} y^{5}) 2

x^{3} - 7 x^{3} + 5 x - 35

(- 1) - π

What is factor x^6-12x^4+48x^2-64 ?
The solution to factor x^6-12x^4+48x^2-64 is (x+2)^3(x-2)^3