What is factor x^8-4x^6+6x^4-4x^2+1 ?

The solution to factor x^8-4x^6+6x^4-4x^2+1 is (x+1)^4(x-1)^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^8-4x^6+6x^4-4x^2+1

factor

x^{8} - 4 x^{6} + 6 x^{4} - 4 x^{2} + 1

(x + 1)^{4} (x - 1)^{4}

Solution steps

x^{8} - 4 x^{6} + 6 x^{4} - 4 x^{2} + 1

Let

u = x^{2}

= u^{4} - 4 u^{3} + 6 u^{2} - 4 u + 1

Factor

u^{4} - 4 u^{3} + 6 u^{2} - 4 u + 1 : (u - 1) (u - 1) (u - 1) (u - 1)

= (u - 1) (u - 1) (u - 1) (u - 1)

Substitute back

u = x^{2}

= (x^{2} - 1) (x^{2} - 1) (x^{2} - 1) (x^{2} - 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x^{2} - 1) (x^{2} - 1) (x^{2} - 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x + 1) (x - 1) (x^{2} - 1) (x^{2} - 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x + 1) (x - 1) (x + 1) (x - 1) (x^{2} - 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x + 1) (x - 1) (x + 1) (x - 1) (x + 1) (x - 1)

Refine

= (x + 1)^{4} (x - 1)^{4}

[- 25.25]

4 (2 x + 3)^{2} - 12 (2 x + 3) + 5

1.6 \cdot (- x)

3 rs - 5 cr - 15 cs + 25 c^{2}

3 - \frac{2 e ^{3}}{e ^{3} - 1}

What is factor x^8-4x^6+6x^4-4x^2+1 ?
The solution to factor x^8-4x^6+6x^4-4x^2+1 is (x+1)^4(x-1)^4