What is factor 4qa+5q^2+4da+5dq ?

The solution to factor 4qa+5q^2+4da+5dq is (d+q)(4a+5q)

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factor 4qa+5q^2+4da+5dq

factor

4 q a + 5 q^{2} + 4 d a + 5 d q

(d + q) (4 a + 5 q)

Solution steps

4 q a + 5 q^{2} + 4 d a + 5 d q

Factor out common term

4 a

= 4 a (q + d) + 5 q^{2} + 5 d q

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

q^{2} = qq

= 4 a (d + q) + 5 qq + 5 d q

Factor out common term

5 q

= 4 a (d + q) + 5 q (q + d)

Factor out common term

(d + q)

= (d + q) (4 a + 5 q)

a (c t - \frac{b}{a} x)

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\frac{- 36 - 4 11}{29}

- 3 cos (x) (sin (x))^{2}

What is factor 4qa+5q^2+4da+5dq ?
The solution to factor 4qa+5q^2+4da+5dq is (d+q)(4a+5q)