What are the solutions to the equation 3x^2-8=0 ?

The solutions to the equation 3x^2-8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

Find the zeros of 3x^2-8=0

The zeros of 3x^2-8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

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3 x^{2} - 8 = 0

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 1.63299 \dots, x = - 1.63299 \dots

Solution steps

3 x^{2} - 8 = 0

Move

8

to the right side

3 x^{2} = 8

Divide both sides by

3

x^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{3}, x = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

3^{0}

5 x - 4 = 21

\frac{4 e ^{2 (2^{3})}}{12 x ^{2}} \leq 0.001

\frac{( m + 4 )}{( 5 )} + 2 = \frac{m}{3}

9 x^{2} - 49 y^{2}

What are the solutions to the equation 3x^2-8=0 ?
The solutions to the equation 3x^2-8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))
Find the zeros of 3x^2-8=0
The zeros of 3x^2-8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))