What is the derivative of x^3+y^3 ?

The derivative of x^3+y^3 is 3x^2+3y^2(dy)/(dx)

What is the first derivative of x^3+y^3 ?

The first derivative of x^3+y^3 is 3x^2+3y^2(dy)/(dx)

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\frac{d}{d x} (x^{3} + y^{3})

3 x^{2} + 3 y^{2} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{3} + y^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (y^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (y^{3}) = 3 y^{2} \frac{d y}{d x}

= 3 x^{2} + 3 y^{2} \frac{d y}{d x}

27 p y^{2} - 2 q + 18 q y^{2} - 3 p

2 x - 4 \frac{d}{d x} (δ (x))

2 a x + 6 a y + b x + 3 b y

\frac{x ^{2} - 3 x + 2}{x - 4}

10 cos (10 t + 130)

What is the derivative of x^3+y^3 ?
The derivative of x^3+y^3 is 3x^2+3y^2(dy)/(dx)
What is the first derivative of x^3+y^3 ?
The first derivative of x^3+y^3 is 3x^2+3y^2(dy)/(dx)