What is factor (4x^2)^2-8(4x^2)-105 ?

The solution to factor (4x^2)^2-8(4x^2)-105 is (4x^2+7)(4x^2-15)

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factor (4x^2)^2-8(4x^2)-105

factor

(4 x^{2})^{2} - 8 (4 x^{2}) - 105

(4 x^{2} + 7) (4 x^{2} - 15)

Solution steps

(4 x^{2})^{2} - 8 (4 x^{2}) - 105

Write in the standard form

a x^{2} + b x + c

= (4 x^{2})^{2} - 84 x^{2} - 105

Break the expression into groups

= ((4 x^{2})^{2} + 74 x^{2}) + (- 154 x^{2} - 105)

Factor out

4 x^{2}

from

(4 x^{2})^{2} + 74 x^{2} : 4 x^{2} (4 x^{2} + 7)

Factor out

- 15

from

- 154 x^{2} - 105 : - 15 (4 x^{2} + 7)

= 4 x^{2} (4 x^{2} + 7) - 15 (4 x^{2} + 7)

Factor out common term

4 x^{2} + 7

= (4 x^{2} + 7) (4 x^{2} - 15)

(cos (x + y))^{2}

m p + m q - 3 p - 3 q

ln (s) in x (sin (x))

a e^{4 x} - a e^{- 4 x}

(x - 1)^{3} - 27

What is factor (4x^2)^2-8(4x^2)-105 ?
The solution to factor (4x^2)^2-8(4x^2)-105 is (4x^2+7)(4x^2-15)