What is factor-cos(2a-4θ)sin(2a-4θ) ?

The solution to factor-cos(2a-4θ)sin(2a-4θ) is -cos(2(a-2θ))sin(2(a-2θ))

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factor-cos(2a-4θ)sin(2a-4θ)

factor

- cos (2 a - 4 θ) sin (2 a - 4 θ)

- cos (2 (a - 2 θ)) sin (2 (a - 2 θ))

Solution steps

- cos (2 a - 4 θ) sin (2 a - 4 θ)

Factor

2 a - 4 θ : 2 (a - 2 θ)

= - sin (- 4 θ + 2 a) cos (2 (- 2 θ + a))

Factor

2 a - 4 θ : 2 (a - 2 θ)

= - cos (2 (- 2 θ + a)) sin (2 (- 2 θ + a))

x^{2} + 4 x^{2} - 4 x - 16

4 x^{3 + 3 x^{2} + 5 x + 9}

[ab]

e^{5 x} \cdot (6 b sin (6 x))

32 m^{15} - 243 n^{10}

What is factor-cos(2a-4θ)sin(2a-4θ) ?
The solution to factor-cos(2a-4θ)sin(2a-4θ) is -cos(2(a-2θ))sin(2(a-2θ))