What are the solutions to the equation log_{8}(2)+log_{8}(4)x^2=1 ?

The solutions to the equation log_{8}(2)+log_{8}(4)x^2=1 are x=1,x=-1

Find the zeros of log_{8}(2)+log_{8}(4)x^2=1

The zeros of log_{8}(2)+log_{8}(4)x^2=1 are x=1,x=-1

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lo g_{8} (2) + lo g_{8} (4) x^{2} = 1

x = 1, x = - 1

Solution steps

lo g_{8} (2) + lo g_{8} (4) x^{2} = 1

Move

lo g_{8} (2)

to the right side

lo g_{8} (4) x^{2} = 1 - \frac{1}{3}

Simplify

1 - \frac{1}{3} : \frac{2}{3}

lo g_{8} (4) x^{2} = \frac{2}{3}

Simplify

lo g_{8} (4) : \frac{2}{3}

\frac{2}{3} x^{2} = \frac{2}{3}

Multiply both sides by

3

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

6 x^{2} + 30 x + 36

\frac{x}{3} + 7 = 10

- 3 + 7 x \geq 53

x^{3} - 9 x^{2} + 7 x - 63

41.1 = \frac{4 x ^{2}}{( 9.61 ) ^{2}}

What are the solutions to the equation log_{8}(2)+log_{8}(4)x^2=1 ?
The solutions to the equation log_{8}(2)+log_{8}(4)x^2=1 are x=1,x=-1
Find the zeros of log_{8}(2)+log_{8}(4)x^2=1
The zeros of log_{8}(2)+log_{8}(4)x^2=1 are x=1,x=-1