What is factor (ab+1)(a+1)(b+1)+ab ?

The solution to factor (ab+1)(a+1)(b+1)+ab is a^2b^2+a^2b+ab^2+3ab+a+b+1

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factor (ab+1)(a+1)(b+1)+ab

factor

(ab + 1) (a + 1) (b + 1) + ab

a^{2} b^{2} + a^{2} b + a b^{2} + 3 ab + a + b + 1

Solution steps

(ab + 1) (a + 1) (b + 1) + ab

Expand

(ab + 1) (a + 1) (b + 1) : a^{2} b^{2} + a^{2} b + a b^{2} + 2 ab + a + b + 1

= a^{2} b^{2} + a^{2} b + a b^{2} + 2 ab + a + b + 1 + ab

Simplify

a^{2} b^{2} + a^{2} b + a b^{2} + 2 ab + a + b + 1 + ab : a^{2} b^{2} + a^{2} b + a b^{2} + 3 ab + a + b + 1

= a^{2} b^{2} + a^{2} b + a b^{2} + 3 ab + a + b + 1

e^{ω t} + e^{- ω t}

x^{2} - 25

(x + Δ x) 3 - x^{3}

\frac{x ^{624} - 1}{x - 1}

(\frac{ln ( 40 )}{ln ( 5 )}) - 4

What is factor (ab+1)(a+1)(b+1)+ab ?
The solution to factor (ab+1)(a+1)(b+1)+ab is a^2b^2+a^2b+ab^2+3ab+a+b+1