What are the solutions to the equation (y-4)^2=7 ?

The solutions to the equation (y-4)^2=7 are y=sqrt(7)+4,y=-sqrt(7)+4

Find the zeros of (y-4)^2=7

The zeros of (y-4)^2=7 are y=sqrt(7)+4,y=-sqrt(7)+4

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(y - 4)^{2} = 7

y = 7 + 4, y = - 7 + 4

Decimal Notation

y = 6.64575 \dots, y = 1.35424 \dots

Solution steps

(y - 4)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 4 = 7 : y = 7 + 4

Solve

y - 4 = - 7 : y = - 7 + 4

The solutions to the quadratic equation are:

y = 7 + 4, y = - 7 + 4

x + (\frac{x}{3}) \leq 20

x^{4} + 3 x^{2} - 40

2 x^{5} + 2 x^{4} - 5 x^{3} - 5 x^{2} - 3 x - 3

\frac{1}{3} \cdot \frac{2}{3}

\frac{\frac{1}{1}}{2}

What are the solutions to the equation (y-4)^2=7 ?
The solutions to the equation (y-4)^2=7 are y=sqrt(7)+4,y=-sqrt(7)+4
Find the zeros of (y-4)^2=7
The zeros of (y-4)^2=7 are y=sqrt(7)+4,y=-sqrt(7)+4