What is factor 36^{2018}+36^{2019} ?

The solution to factor 36^{2018}+36^{2019} is 6^{4036}*37

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factor 36^{2018}+36^{2019}

factor

3 6^{2018} + 3 6^{2019}

6^{4036} \cdot 37

Solution steps

3 6^{2018} + 3 6^{2019}

36 = 2^{2} \cdot 3^{2}

= (2^{2})^{2018} (3^{2})^{2018} + (2^{2} \cdot 3^{2})^{2019}

Apply exponent rule:

(ab)^{c} = a^{c} b^{c}

= (2^{2})^{2018} (3^{2})^{2018} + (2^{2})^{2019} (3^{2})^{2019}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

2^{2019 \cdot 2} = 2^{2018 \cdot 2} \cdot 2^{2}, 3^{2019 \cdot 2} = 3^{2018 \cdot 2} \cdot 3^{2}

= 2^{2018 \cdot 2} \cdot 3^{2018 \cdot 2} + 2^{2018 \cdot 2} \cdot 2^{2} \cdot 3^{2018 \cdot 2} \cdot 3^{2}

Factor out common term

3^{2018 \cdot 2} \cdot 2^{2018 \cdot 2}

= 3^{2018 \cdot 2} \cdot 2^{2018 \cdot 2} (1 + 2^{2} \cdot 3^{2})

Refine

= 6^{4036} \cdot 37

(- 67.4) + (+ 51.3 p)

l (e^{4} t cos (t))

e^{34704} + e^{3555} \cdot 7

9^{2} - 30 x + 25

- 200

What is factor 36^{2018}+36^{2019} ?
The solution to factor 36^{2018}+36^{2019} is 6^{4036}*37