What is factor 8x^6+y^9z^3 ?

The solution to factor 8x^6+y^9z^3 is (2x^2+y^3z)(4x^4-2x^2y^3z+y^6z^2)

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factor 8x^6+y^9z^3

factor

8 x^{6} + y^{9} z^{3}

(2 x^{2} + y^{3} z) (4 x^{4} - 2 x^{2} y^{3} z + y^{6} z^{2})

Solution steps

8 x^{6} + y^{9} z^{3}

Rewrite

8 x^{6}

(2 x^{2})^{3}

Rewrite

y^{9} z^{3}

(y^{3} z)^{3}

= (2 x^{2})^{3} + (y^{3} z)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 x^{2})^{3} + (y^{3} z)^{3} = (2 x^{2} + y^{3} z) ((2 x^{2})^{2} - y^{3} z 2 x^{2} + (y^{3} z)^{2})

= (y^{3} z + 2 x^{2}) ((y^{3} z)^{2} - y^{3} z 2 x^{2} + (2 x^{2})^{2})

Simplify

(2 x^{2} + y^{3} z) ((2 x^{2})^{2} - y^{3} z \cdot 2 x^{2} + (y^{3} z)^{2}) : (2 x^{2} + y^{3} z) (4 x^{4} - 2 x^{2} y^{3} z + y^{6} z^{2})

= (2 x^{2} + y^{3} z) (4 x^{4} - 2 x^{2} y^{3} z + y^{6} z^{2})

(x + y)^{(x + y)}

82

\frac{x ^{2} + 2 x}{x + 2}

(3 x + 12)^{'} + 15

2 a + 2 b + a x + b x

What is factor 8x^6+y^9z^3 ?
The solution to factor 8x^6+y^9z^3 is (2x^2+y^3z)(4x^4-2x^2y^3z+y^6z^2)