What is factor 2^{m-5}+2^{n-5} ?

The solution to factor 2^{m-5}+2^{n-5} is 1/32 (2^m+2^n)

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factor 2^{m-5}+2^{n-5}

factor

2^{m - 5} + 2^{n - 5}

\frac{1}{32} (2^{m} + 2^{n})

Solution steps

2^{m - 5} + 2^{n - 5}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

= 2^{- 5} \cdot 2^{m} + 2^{- 5} \cdot 2^{n}

Factor out common term

2^{- 5}

= 2^{- 5} (2^{m} + 2^{n})

Refine

= \frac{1}{32} (2^{n} + 2^{m})

16 x^{3} - 54 x^{3}

[(a + b) + 1] \cdot [(a + b) - 1]

16 (y + 3)^{2} - 40 (y + 3) + 25

5 e^{2} - 2 e - 7

ln (2 + 2 i)

What is factor 2^{m-5}+2^{n-5} ?
The solution to factor 2^{m-5}+2^{n-5} is 1/32 (2^m+2^n)