What is factor 2sin^2(θ)+3sin(θ)+1 ?

The solution to factor 2sin^2(θ)+3sin(θ)+1 is (2sin(θ)+1)(sin(θ)+1)

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factor 2sin^2(θ)+3sin(θ)+1

factor

2 sin^{2} (θ) + 3 sin (θ) + 1

(2 sin (θ) + 1) (sin (θ) + 1)

Solution steps

2 sin^{2} (θ) + 3 sin (θ) + 1

Break the expression into groups

= (2 sin^{2} (θ) + sin (θ)) + (2 sin (θ) + 1)

Factor out

sin (θ)

from

2 sin^{2} (θ) + sin (θ) : sin (θ) (2 sin (θ) + 1)

= sin (θ) (2 sin (θ) + 1) + (2 sin (θ) + 1)

Factor out common term

2 sin (θ) + 1

= (2 sin (θ) + 1) (sin (θ) + 1)

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What is factor 2sin^2(θ)+3sin(θ)+1 ?
The solution to factor 2sin^2(θ)+3sin(θ)+1 is (2sin(θ)+1)(sin(θ)+1)