What is factor x^{2x}+x^x-12 ?

The solution to factor x^{2x}+x^x-12 is (x^x-3)(x^x+4)

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factor x^{2x}+x^x-12

factor

x^{2 x} + x^{x} - 12

(x^{x} - 3) (x^{x} + 4)

Solution steps

x^{2 x} + x^{x} - 12

Apply exponent rule:

a^{b c} = (a^{b})^{c}

x^{2 x} = (x^{x})^{2}

= (x^{x})^{2} + x^{x} - 12

Break the expression into groups

= ((x^{x})^{2} - 3 x^{x}) + (4 x^{x} - 12)

Factor out

x^{x}

from

(x^{x})^{2} - 3 x^{x} : x^{x} (x^{x} - 3)

Factor out

4

from

4 x^{x} - 12 : 4 (x^{x} - 3)

= x^{x} (x^{x} - 3) + 4 (x^{x} - 3)

Factor out common term

x^{x} - 3

= (x^{x} - 3) (x^{x} + 4)

x^{2} - \frac{62}{6}

(5 x + 1)^{2} + 16 (5 x + 1) + 64

4^{4}

y^{8} - 2 y^{4} - 80

- (cos (x))

What is factor x^{2x}+x^x-12 ?
The solution to factor x^{2x}+x^x-12 is (x^x-3)(x^x+4)