What are the solutions to the equation y^2-5y-9=0 ?

The solutions to the equation y^2-5y-9=0 are y=(5+sqrt(61))/2 ,y=(5-sqrt(61))/2

Find the zeros of y^2-5y-9=0

The zeros of y^2-5y-9=0 are y=(5+sqrt(61))/2 ,y=(5-sqrt(61))/2

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y^{2} - 5 y - 9 = 0

y = \frac{5 + 61}{2}, y = \frac{5 - 61}{2}

Decimal Notation

y = 6.40512 \dots, y = - 1.40512 \dots

Solution steps

y^{2} - 5 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 9) = 61

y_{1, 2} = \frac{- ( - 5 ) \pm 61}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 61}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 61}{2 \cdot 1}

y = \frac{- ( - 5 ) + 61}{2 \cdot 1} : \frac{5 + 61}{2}

y = \frac{- ( - 5 ) - 61}{2 \cdot 1} : \frac{5 - 61}{2}

The solutions to the quadratic equation are:

y = \frac{5 + 61}{2}, y = \frac{5 - 61}{2}

9 m^{2} - 25 mn - 6 n^{2}

3 \geq ∣ 4 x + 1 ∣

- 16 x^{2} + 24 x + 240

8 x^{3} + 8 x y^{2} - 98 x

- x > - 2

What are the solutions to the equation y^2-5y-9=0 ?
The solutions to the equation y^2-5y-9=0 are y=(5+sqrt(61))/2 ,y=(5-sqrt(61))/2
Find the zeros of y^2-5y-9=0
The zeros of y^2-5y-9=0 are y=(5+sqrt(61))/2 ,y=(5-sqrt(61))/2