What is the first d/(dy)((M)(xydx)) ?

The first d/(dy)((M)(xydx)) is Mx^2d

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d/(dy)((M)(xydx))

\frac{d}{d y} ((M) (x y d x))

M x^{2} d

Solution steps

\frac{d}{d y} ((M) (x y d x))

Simplify

(M) (x y d x) : M x^{2} y d

= \frac{d}{d y} (M x^{2} y d)

Treat

M, x, d

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= M x^{2} d \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= M x^{2} d \cdot 1

Simplify

= M x^{2} d

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