What are the solutions to the equation x^2-5=2x ?

The solutions to the equation x^2-5=2x are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x^2-5=2x

The zeros of x^2-5=2x are x=1+sqrt(6),x=1-sqrt(6)

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x^{2} - 5 = 2 x

x = 1 + 6, x = 1 - 6

Solution steps

x^{2} - 5 = 2 x

Move

2 x

to the left side

x^{2} - 5 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

s + \frac{1}{4} s = - 6 - \frac{3}{2}

12 y \geq 1

7 (x - 3) + 4 x = 1

\frac{5}{u} + 14 > 41

x^{2} - 6 x

What are the solutions to the equation x^2-5=2x ?
The solutions to the equation x^2-5=2x are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x^2-5=2x
The zeros of x^2-5=2x are x=1+sqrt(6),x=1-sqrt(6)