What is factor 2x^2+8xz-xy-4yz ?

The solution to factor 2x^2+8xz-xy-4yz is (x+4z)(2x-y)

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factor 2x^2+8xz-xy-4yz

factor

2 x^{2} + 8 x z - x y - 4 yz

(x + 4 z) (2 x - y)

Solution steps

2 x^{2} + 8 x z - x y - 4 yz

Factor

2 x^{2} + 8 x z : 2 x (x + 4 z)

Factor

- x y - 4 yz : - y (x + 4 z)

= 2 x (x + 4 z) - y (x + 4 z)

Factor out common term

(x + 4 z)

= (x + 4 z) (2 x - y)

6 ab - d^{2} - 3 b d + 2 a d

\frac{x - 7}{x ^{2} + 6 x + 5}

x^{2} + (n + 1)

sin (4 x + 2)

\frac{279 - 3 73}{8}

What is factor 2x^2+8xz-xy-4yz ?
The solution to factor 2x^2+8xz-xy-4yz is (x+4z)(2x-y)