What is (-9-2i)/(-8-i) ?

The solution to (-9-2i)/(-8-i) is 74/65+7/65 i

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simplify (-9-2i)/(-8-i)

simplify

\frac{- 9 - 2 i}{- 8 - i}

\frac{74}{65} + \frac{7}{65} i

Solution steps

\frac{- 9 - 2 i}{- 8 - i}

Multiply by the conjugate

\frac{- 8 + i}{- 8 + i}

= \frac{( - 9 - 2 i ) ( - 8 + i )}{( - 8 - i ) ( - 8 + i )}

Simplify

\frac{( - 9 - 2 i ) ( - 8 + i )}{( - 8 - i ) ( - 8 + i )} : \frac{74 + 7 i}{65}

= \frac{74 + 7 i}{65}

Rewrite in standard complex form:

\frac{74}{65} + \frac{7}{65} i

= \frac{74}{65} + \frac{7}{65} i

e^{2 l n (7)}

h (- 2) = \frac{6 + ( - 2 ) ^{3}}{( - 2 ) ^{3}}

\frac{8 a ^{4} b ^{- 6}}{4 a ^{7} b ^{- 6}}

5 \cdot \frac{1}{2}

6 \geq 2 y