What is factor 1+ab+m(a+b)+m(ab+1)+a+b ?

The solution to factor 1+ab+m(a+b)+m(ab+1)+a+b is (1+a+b+ab)(m+1)

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factor 1+ab+m(a+b)+m(ab+1)+a+b

factor

1 + ab + m (a + b) + m (ab + 1) + a + b

(1 + a + b + ab) (m + 1)

Solution steps

1 + ab + m (a + b) + m (ab + 1) + a + b

Factor out common term

m

= m (a + b + 1 + ab) + a + b + 1 + ab

Rewrite as

= (1 + a + b + ab) m + 1 \cdot (1 + a + b + ab)

Factor out common term

(1 + a + b + ab)

= (1 + a + b + ab) (m + 1)

(2 n + 4 \frac{k}{n})^{2}

2 (x - 1)^{2} + 3 (x - 1) + 1

\frac{( ab - a )}{b ^{2} - b}

R - [5]

402 4_{(5)}

What is factor 1+ab+m(a+b)+m(ab+1)+a+b ?
The solution to factor 1+ab+m(a+b)+m(ab+1)+a+b is (1+a+b+ab)(m+1)