What is factor (n+3)^2+2n ?

The solution to factor (n+3)^2+2n is (n+4-sqrt(7))(n+4+sqrt(7))

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factor (n+3)^2+2n

factor

(n + 3)^{2} + 2 n

(n + 4 - 7) (n + 4 + 7)

Solution steps

(n + 3)^{2} + 2 n

(n + 3)^{2} : n^{2} + 6 n + 9

= n^{2} + 6 n + 9 + 2 n

Simplify

n^{2} + 6 n + 9 + 2 n : n^{2} + 8 n + 9

= n^{2} + 8 n + 9

Solve

n^{2} + 8 n + 9 = 0 : n = - 4 + 7, n = - 4 - 7

Polynom can therefore be factored into

= (n - (- 4 + 7)) (n - (- 4 - 7))

Refine

= (n + 4 - 7) (n + 4 + 7)

k^{r + m} - 4 k^{r} + k^{m} - 4

7.6

2 x (3 x^{3} - x^{3})

m^{2} + 2 m + (- 1)

4^{2} \cdot 4 \cdot 4^{7}

What is factor (n+3)^2+2n ?
The solution to factor (n+3)^2+2n is (n+4-sqrt(7))(n+4+sqrt(7))