What is factor (9y^2)^3-(4z)^3 ?

The solution to factor (9y^2)^3-(4z)^3 is (9y^2-4z)(81y^4+36y^2z+16z^2)

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factor (9y^2)^3-(4z)^3

factor

(9 y^{2})^{3} - (4 z)^{3}

(9 y^{2} - 4 z) (81 y^{4} + 36 y^{2} z + 16 z^{2})

Solution steps

(9 y^{2})^{3} - (4 z)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(9 y^{2})^{3} - (4 z)^{3} = (9 y^{2} - 4 z) ((9 y^{2})^{2} + 9 y^{2} 4 z + (4 z)^{2})

= (9 y^{2} - 4 z) ((9 y^{2})^{2} + 9 y^{2} 4 z + (4 z)^{2})

Simplify

(9 y^{2} - 4 z) ((9 y^{2})^{2} + 9 y^{2} \cdot 4 z + (4 z)^{2}) : (9 y^{2} - 4 z) (81 y^{4} + 36 y^{2} z + 16 z^{2})

= (9 y^{2} - 4 z) (81 y^{4} + 36 y^{2} z + 16 z^{2})

sin (sin^{-} (1) (x))

20 + 55

(2 + 3)^{2}

(5 a - 3 b)^{2} + 8 (5 a - 3 b) + 16

500 - 5 x^{50}

What is factor (9y^2)^3-(4z)^3 ?
The solution to factor (9y^2)^3-(4z)^3 is (9y^2-4z)(81y^4+36y^2z+16z^2)