What is factor 0.04x^2+0.48x+1.44 ?

The solution to factor 0.04x^2+0.48x+1.44 is (0.2x+1.2)^2

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factor 0.04x^2+0.48x+1.44

factor

0.04 x^{2} + 0.48 x + 1.44

(0.2 x + 1.2)^{2}

Solution steps

0.04 x^{2} + 0.48 x + 1.44

Rewrite

0.04 x^{2} + 0.48 x + 1.44

(0.04 x)^{2} + 2 \cdot 0.2 x \cdot 1.2 + (1.44)^{2}

= (0.04 x)^{2} + 2 \cdot 0.2 x \cdot 1.2 + (1.44)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 0.2 x, b = 1.2

= (0.2 x + 1.2)^{2}

(- 3 m^{2} n^{5}) - 1

(x + y)^{2} - 5 (x + y) + 6

\frac{x ^{2} + x - 12}{x - 3}

s^{2} + sz + 5 s n + 5 z n

42 r^{2} - 49 r^{2} + 18 r - 21

What is factor 0.04x^2+0.48x+1.44 ?
The solution to factor 0.04x^2+0.48x+1.44 is (0.2x+1.2)^2