What are the solutions to the equation -26x^2+27x-1=0 ?

The solutions to the equation -26x^2+27x-1=0 are x= 1/26 ,x=1

Find the zeros of -26x^2+27x-1=0

The zeros of -26x^2+27x-1=0 are x= 1/26 ,x=1

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- 26 x^{2} + 27 x - 1 = 0

x = \frac{1}{26}, x = 1

Decimal Notation

x = 0.03846 \dots, x = 1

Solution steps

- 26 x^{2} + 27 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 ( - 26 ) ( - 1 )}{2 ( - 26 )}

2 7^{2} - 4 (- 26) (- 1) = 25

x_{1, 2} = \frac{- 27 \pm 25}{2 ( - 26 )}

Separate the solutions

x_{1} = \frac{- 27 + 25}{2 ( - 26 )}, x_{2} = \frac{- 27 - 25}{2 ( - 26 )}

x = \frac{- 27 + 25}{2 ( - 26 )} : \frac{1}{26}

x = \frac{- 27 - 25}{2 ( - 26 )} : 1

The solutions to the quadratic equation are:

x = \frac{1}{26}, x = 1

∣ 2 x - 9 ∣ < 7

(\frac{2}{1} - \frac{1}{2}) (\frac{3}{1} - \frac{2}{3}) + 4 1^{2}

\frac{8}{27} (1 0^{\frac{3}{2}} - 1)

(- 4 x^{5} y^{2})^{2}

What are the solutions to the equation -26x^2+27x-1=0 ?
The solutions to the equation -26x^2+27x-1=0 are x= 1/26 ,x=1
Find the zeros of -26x^2+27x-1=0
The zeros of -26x^2+27x-1=0 are x= 1/26 ,x=1