What is factor 4a^2-1-a^2+4a ?

The solution to factor 4a^2-1-a^2+4a is 3(a-(-2+sqrt(7))/3)(a+(2+sqrt(7))/3)

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factor 4a^2-1-a^2+4a

factor

4 a^{2} - 1 - a^{2} + 4 a

3 (a - \frac{- 2 + 7}{3}) (a + \frac{2 + 7}{3})

Solution steps

4 a^{2} - 1 - a^{2} + 4 a

Group like terms

= 4 a^{2} - a^{2} + 4 a - 1

Add similar elements:

4 a^{2} - a^{2} = 3 a^{2}

= 3 a^{2} + 4 a - 1

Rewrite as

= 3 (a^{2} + \frac{4 a}{3} - \frac{1}{3})

Factor

a^{2} + \frac{4 a}{3} - \frac{1}{3} : (a + \frac{2 + 7}{3}) (a - \frac{7 - 2}{3})

3 (a + \frac{2 + 7}{3}) (a - \frac{7 - 2}{3})

25

5 (a)^{2}

a + (- b) + c

x^{2} + x + y - z - (y - z)^{2}

(ln (x))^{s i n h (x)}

What is factor 4a^2-1-a^2+4a ?
The solution to factor 4a^2-1-a^2+4a is 3(a-(-2+sqrt(7))/3)(a+(2+sqrt(7))/3)