What is factor 3y^6+7y^4-15y^2-35 ?

The solution to factor 3y^6+7y^4-15y^2-35 is (3y^2+7)(y^4-5)

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factor 3y^6+7y^4-15y^2-35

factor

3 y^{6} + 7 y^{4} - 15 y^{2} - 35

(3 y^{2} + 7) (y^{4} - 5)

Solution steps

3 y^{6} + 7 y^{4} - 15 y^{2} - 35

Let

u = y^{2}

= 3 u^{3} + 7 u^{2} - 15 u - 35

Factor

3 u^{3} + 7 u^{2} - 15 u - 35 : (3 u + 7) (u^{2} - 5)

= (3 u + 7) (u^{2} - 5)

Substitute back

u = y^{2}

= (3 y^{2} + 7) (y^{4} - 5)

25 x y - 64 p^{2} - 40 x p + 40 p y

b x^{3} - b y

c^{2} + 11 c + 30.25

C (13.5)

\frac{15 + 5 5}{2}

What is factor 3y^6+7y^4-15y^2-35 ?
The solution to factor 3y^6+7y^4-15y^2-35 is (3y^2+7)(y^4-5)