What is the derivative of 3x^2+2xy-y^2 ?

The derivative of 3x^2+2xy-y^2 is 6x+2(y+x(dy)/(dx))-2y(dy)/(dx)

What is the first derivative of 3x^2+2xy-y^2 ?

The first derivative of 3x^2+2xy-y^2 is 6x+2(y+x(dy)/(dx))-2y(dy)/(dx)

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\frac{d}{d x} (3 x^{2} + 2 x y - y^{2})

6 x + 2 (y + x \frac{d y}{d x}) - 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x y - y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x y) - \frac{d}{d x} (y^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 6 x + 2 (y + x \frac{d y}{d x}) - 2 y \frac{d y}{d x}

(cos (5 t))^{2}

\frac{x}{x ^{2} - 5 x}

2 c + 3 b c - 2 d - 3 b d

4 - 1.3 - 2000 x

p^{2} + pq - p r - q r

What is the derivative of 3x^2+2xy-y^2 ?
The derivative of 3x^2+2xy-y^2 is 6x+2(y+x(dy)/(dx))-2y(dy)/(dx)
What is the first derivative of 3x^2+2xy-y^2 ?
The first derivative of 3x^2+2xy-y^2 is 6x+2(y+x(dy)/(dx))-2y(dy)/(dx)