What is factor 4(c+2)^2+5(c+2)-6 ?

The solution to factor 4(c+2)^2+5(c+2)-6 is (4c+5)(c+4)

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factor 4(c+2)^2+5(c+2)-6

factor

4 (c + 2)^{2} + 5 (c + 2) - 6

(4 c + 5) (c + 4)

Solution steps

4 (c + 2)^{2} + 5 (c + 2) - 6

Break the expression into groups

= (4 (c + 2)^{2} - 3 (c + 2)) + (8 (c + 2) - 6)

Factor out

(c + 2)

from

4 (c + 2)^{2} - 3 (c + 2) : (c + 2) (4 (c + 2) - 3)

Factor out

2

from

8 (c + 2) - 6 : 2 (4 (c + 2) - 3)

= (c + 2) (4 (c + 2) - 3) + 2 (4 (c + 2) - 3)

Factor out common term

4 (c + 2) - 3

= (4 (c + 2) - 3) ((c + 2) + 2)

Refine

= (c + 4) (4 (c + 2) - 3)

Expand

4 (c + 2) - 3 : 4 c + 5

= (4 c + 5) (c + 4)

(sin (x))^{l n (x)}

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i z \frac{z - 1}{z ^{2} - 1}

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What is factor 4(c+2)^2+5(c+2)-6 ?
The solution to factor 4(c+2)^2+5(c+2)-6 is (4c+5)(c+4)