What is factor 2sin^2(θ)-5sin(θ)-3 ?

The solution to factor 2sin^2(θ)-5sin(θ)-3 is (2sin(θ)+1)(sin(θ)-3)

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factor 2sin^2(θ)-5sin(θ)-3

factor

2 sin^{2} (θ) - 5 sin (θ) - 3

(2 sin (θ) + 1) (sin (θ) - 3)

Solution steps

2 sin^{2} (θ) - 5 sin (θ) - 3

Break the expression into groups

= (2 sin^{2} (θ) + sin (θ)) + (- 6 sin (θ) - 3)

Factor out

sin (θ)

from

2 sin^{2} (θ) + sin (θ) : sin (θ) (2 sin (θ) + 1)

Factor out

- 3

from

- 6 sin (θ) - 3 : - 3 (2 sin (θ) + 1)

= sin (θ) (2 sin (θ) + 1) - 3 (2 sin (θ) + 1)

Factor out common term

2 sin (θ) + 1

= (2 sin (θ) + 1) (sin (θ) - 3)

x y e^{(- x - y)}

4 (u - 5)^{'} - 8 u

ln (2 + i 23)

(arccos (y))^{2}

d (0) d a_{0}

What is factor 2sin^2(θ)-5sin(θ)-3 ?
The solution to factor 2sin^2(θ)-5sin(θ)-3 is (2sin(θ)+1)(sin(θ)-3)